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The angular width of the central maximum in a single slit diffraction pattern is 60°. The width of the slit is 1 μm. The slit is illuminated by monochromatic plane waves. If another slit of same width is made near it, Young’s fringes can be observed on a screen placed at a distance 50 cm from the slits. If the observed fringe width is 1 cm, what is slit separation distance? (i.e. distance between the centres of each slit.)

  1. 25 μm
  2. 50 μm
  3. 75 μm
  4. 100 μm

Answer (Detailed Solution Below)

Option 1 : 25 μm
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Detailed Solution

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In diffraction

d sin 30° = λ

Now, let x is the separation between two slits.

Young’s fringe width (ω) = 1 cm = 10-2 m

⇒ x = 25 d = 25 × 1 μm = 25 μm

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