Question
Download Solution PDFఒకవేళ గోళం యొక్క వ్యాసం 3.5 cm అయితే, అప్పుడు గోళం యొక్క సంపూర్ణతల వైశాల్యం ఎంత?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చింది:
ఒక గోళం యొక్క వ్యాసం 3.5 సెం.మీ.
ఉపయోగించిన భావన:
మొత్తం ఉపరితల వైశాల్యం = 4πr2
ఇక్కడ r = వ్యాసార్థం
గణన:
మొత్తం ఉపరితల వైశాల్యం = 4 × 22/7 × (3.5/2)2
⇒ 4 × 22/7 × 12.25/4
⇒ 22/7 × 12.25
⇒ 38.5
∴ గోళం యొక్క మొత్తం ఉపరితల వైశాల్యం 38.5 సెం.మీ2.
Last updated on Jul 19, 2025
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