ఒక విద్యుత్ బల్బు 200 V జనరేటర్కు అనుసంధానం చేయబడింది. అందులో విద్యుత్ ప్రవాహం 0.5 A అయితే బల్బు యొక్క విద్యుత్ శక్తి

This question was previously asked in
ALP CBT 2 Physics and Maths Previous Paper 4 (Held On: 22 Jan 2019 Shift 1)
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  1. 10 W
  2. 1000 W
  3. 1 W
  4. 100 W

Answer (Detailed Solution Below)

Option 4 : 100 W
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Detailed Solution

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కాన్సెప్ట్:

  • విద్యుత్ శక్తి: విద్యుత్ శక్తి ఇతర రకాల శక్తిలోకి ప్రవహించే రేటును విద్యుత్ శక్తి అంటారు.అనగా

\(P = \frac{W}{t} = VI = {I^2}R = \frac{{{V^2}}}{R}\)

V = సంభావ్య వ్యత్యాసం, R = నిరోధకత మరియు I = విద్యుత్ ప్రవాహం.

గణన (లెక్కింపు): 

ఇవ్వబడినది - సంభావ్య వ్యత్యాసం (V) = 200 V మరియు విద్యుత్ ప్రవాహం (I) = 0.5 A

  • విద్యుత్ శక్తి క్రింది విధంగా వ్రాయవచ్చు,

​⇒ P = VI

⇒ P = 200 × 0.5 = 100 W

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