Sucrose concentration C0 decreases with time and with rate constant k as

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BPSC AE Paper 3 (General Studies) 10 Nov 2022 Official Paper
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  1. C = -C0 kt2
  2. C =  Clog kt
  3. C = C0e-kt
  4. C = -C0kt

Answer (Detailed Solution Below)

Option 3 : C = C0e-kt
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Detailed Solution

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Concept:

  1. First-Order Kinetics:- The rate of decomposition of a substance is often described by first-order kinetics, where the rate of change of concentration is proportional to the concentration.
  2. Rate Law for First-Order Reactions:- The mathematical form of the first-order reaction is given by: Integrating this differential equation leads to an exponential decay function.

Explanation:

The integrated form of the rate law for a first-order reaction is:

The left side integrates to ln C) and the right side integrates to (-kt):

]

Exponentiate both sides to solve for ( C ):

[ } ]

To determine the constant, consider the initial condition when ( t = 0 ), ( C = C0 ):

[ ]

Therefore, the constant is (ln C0) and we can write:

  • C = C0 e{-kt}

This equation indicates that the concentration of sucrose C decreases exponentially with time t and the rate constant k .

Conclusion:

The correct answer is C = C0e-kt

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