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Specific weight of water is

This question was previously asked in
JKSSB JE Civil Jal Shakti 6 Dec 2022 Official Paper (Shift 1)
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  1. 1000 kN/m3
  2. 9.0 kN/m3
  3. 1000 kg/m3
  4. 9.8 kN/m3

Answer (Detailed Solution Below)

Option 4 : 9.8 kN/m3
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Detailed Solution

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Concept:

Specific weight(γ)

= Density(ρ) × acc. due to gravity (g) 

Calculation:

Given:

ρ = 1000 kg/m3, g = 9.81 m/s2

Now,
Specific weight(γ) = Density(ρ) × acc. due to gravity (g) 
γ = 1000 × 9.81 = 9.81 × 103 N/m3

Thus, Specific weight of water in S.I. units is equal to 9.81  kN/m3

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