Question
Download Solution PDFSelect the correct pair of bond oder.
This question was previously asked in
AIIMS BSc NURSING 2023 Memory-Based Paper
Answer (Detailed Solution Below)
Option 2 :
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AIIMS BSc NURSING 2024 Memory-Based Paper
100 Qs.
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Detailed Solution
Download Solution PDFCONCEPT:
Bond Order in Molecules
B.O. = (Number of bonding electrons - Number of anti-bonding electrons) / 2
- Bond order is defined as the number of chemical bonds between a pair of atoms. In molecular orbital theory, bond order (B.O.) can be calculated using the formula:
- For molecules with multiple bonds or resonance structures, bond order is often fractional, representing an average of bond strengths.
- Let’s consider the molecules provided and calculate their bond orders:
EXPLANATION:
- NO+ (Nitrosonium ion):
- NO has 11 electrons, but NO+ has one less electron due to the positive charge.
- The bond order of NO+ is 3, as it has a triple bond with 10 bonding electrons and 4 anti-bonding electrons.
- CO (Carbon Monoxide):
- CO has 10 electrons in the bonding molecular orbitals and 4 electrons in the anti-bonding molecular orbitals.
- The bond order of CO is 3, indicating a triple bond between C and O.
- O22− (Peroxide ion):
- O22− has 12 electrons in bonding orbitals and 6 electrons in anti-bonding orbitals.
- The bond order for O22− is 1, indicating a single bond between the oxygen atoms.
- The correct pair of bond orders is option 2: NO+: 3, CO: 3, O22−: 1.
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