Question
Download Solution PDF\(\rm \frac{cosA+cosB}{sinA-sinB}=\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
\(\rm sinA - sin B = 2cos\frac{A+B}{2}sin\frac{A-B}{2}\)
\(\rm cosA+cosB=2cos\frac{A+B}{2}cos\frac{A-B}{2}\)
Calculation:
\(\rm \frac{cosA+cosB}{sinA-sinB}=\)
\(\rm \frac {2cos\frac{A+B}{2}cos\frac{A-B}{2}}{2cos\frac{A+B}{2}sin\frac{A-B}{2}}\)
=\(\rm cot\frac{A-B}{2}\)
Hence, option (4) is correct.
Last updated on May 19, 2025
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