Question
Download Solution PDFRandom variable x is with uniform distribution in the span [-4, 1], mean and variance of x is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For a uniform distribution defined over the interval \([a, b]\).The formulas for the mean and variance are:
- Mean: \(\mu = \frac{a + b}{2}\)
- Variance: \(\sigma^2 = \frac{(b - a)^2}{12}\)
Given:
a = -4 & b =1
Calculation:
Mean:
\(\mu = \frac{-4 + 1}{2} = \frac{-3}{2} = -1.5\)
Variance:
\(\sigma^2 = \frac{(1 - (-4))^2}{12} = \frac{(5)^2}{12} = \frac{25}{12}\)
Last updated on Jun 24, 2025
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