Question
Download Solution PDFOpen circuit and short circuit tests conducted on a 10 kVA 2000 V/200 V, 50Hz single-phase transformer gave the following readings.
OC test: 200 V, 1.1 A, 81 W
SC test: 30 V, 5 A, 100 W
At what fraction of full load will the transformer operate at maximum efficiency?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFEfficiency of transformer
The maximum efficiency in the transformer occurs at:
Core loss = Copper loss
Open circuit test gives the value of core loss (PC) while short circuit test gives the value of copper loss (PCu)
Calculation
Given, PC = 81 W
The rated current on the HV side of the transformer is:
This rated current is same as the current at which short circuit test is conducted.
Pcufl = 100 W
Last updated on May 29, 2025
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