On a city map it was mentioned “Scale 1 cm = 110 metres”. If the distance between two localities on the map is 15 cm, then the actual distance between the two localities is

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CTET July 2013 Paper - 1 (L - I/II: Hindi/English/Sanskrit)
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  1. 1165 centimetres
  2. 1100 metres
  3. 1500 metres
  4. 1.65 kilometres

Answer (Detailed Solution Below)

Option 4 : 1.65 kilometres
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CTET CT 1: TET CDP (Development)
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Detailed Solution

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Concept:

Distance:

  • The measurement of how much any object moved is called distance.
  • It is a scalar quantity.

Displacement:

  • The minimum distance between two points is called the displacement of the object.
  • It is a vector quantity.

Explanation:

Given - 1 cm = 110 metres is the conversion scale

Therefore, 15 cm will be

As we know, 

  • The magnitude of displacement is equal to the minimum possible distance between two positions. So distance ≥ Displacement.
  • For a moving particle, distance can never be negative or zero while displacement can be (Zero displacement means that body after motion has come back to initial position). i.e., Distance > 0 but Displacement > = or < 0.
  • For motion between two points displacement is single-valued while distance depends on the actual path and so can have many values.
  • For a moving particle, distance can never decrease with time while displacement can.
  • decrease in displacement with time means the body is moving towards the initial position.

Thus, the actual distance between the two localities is 1.65 kilometres.

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