आकृतीमध्ये, एका वर्तुळातील जीवा AB आणि CD बाहेर P बिंदूवर छेदतात. जर AB = 4 सेमी, CD = 11 सेमी आणि PD = 15 सेमी, तर PB ची लांबी काढा:

F2 Shailesh Shraddha 03.12.2020 D2

This question was previously asked in
SSC CGL Tier 2 Quant Previous Paper 3 (Held On: 18 November 2020)
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  1. 10 सेमी
  2. 12 सेमी
  3. 8 सेमी
  4. 14 सेमी

Answer (Detailed Solution Below)

Option 1 : 10 सेमी
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Detailed Solution

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दिलेले आहे: 

AB आणि CD या वर्तुळाच्या दोन जीवा आहेत ज्या बाहेरून P या बिंदूवर छेदतात

AB = 4 सेमी, CD = 11 सेमी आणि PD = 15 सेमी

वापरलेले सूत्र :

जर AB आणि CD या दोन जीवा बाह्य बिंदू P वर छेदतात तर,

PA × PB = PC × PD 

गणना:

F3 Savita SSC 12-5-22 D1

PA ची लांबी 'x' मानू

PC = PD - CD

⇒ 15 - 11

⇒ PC = 4 सेमी

प्रश्नानुसार,

PA × PB = PC × PD 

x × (x + 4) = 15 × 4 

⇒ x = 6 

PB = PA + AB 

⇒ 6 + 4 

⇒ 10 

∴ PB ची लांबी 10 सेमी आहे.

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