Question
Download Solution PDFMean and variance of binomial distribution are
This question was previously asked in
TNUSRB SI 2020 Official Paper (Held on 12 January 2020)
Answer (Detailed Solution Below)
Option 4 : np, npq
Free Tests
View all Free tests >
TNPSC Group 2 CT : General Tamil (Mock Test பயிற்சித் தேர்வு)
27.5 K Users
10 Questions
10 Marks
7 Mins
Detailed Solution
Download Solution PDFThe correct option is 4) np, npq.
Explanation:
In a binomial distribution, the mean (also known as the expected value) and variance are given by:
- Mean (μ) = np
- Variance (σ²) = npq
Here:
- n is the number of trials,
- p is the probability of success on a single trial, and
- q is the probability of failure on a single trial, which is equal to (1 - p).
Last updated on Jun 13, 2025
->TNUSRB SI Written Exam has been postponed.
-> The TNUSRB SI Notification 2025 was released on 4th April 2025.
-> A total of 1299 vacancies have been released.
-> Candidates can apply online from 7th April to 3rd May 2025.
-> The TNUSRB SI Notification has been released for the recruitment of Sub-Inspectors of Police for Taluk and Armed Forces in the Tamil Nadu Police Department.
-> The selection process includes a written test, PMT, PET, endurance test, medical examination, and certificate verification. Refer to the TNUSRB SI Previous Year Papers to prepare well for the exam.