Let f be an entire function that satisfies |f(z)| ≤ ey for all z = x + iy ∈ ℂ, where x, y ∈ ℝ. Which of the following statements is true?

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CSIR UGC (NET) Mathematical Science: Held On (7 June 2023)
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  1. f(z) = ce−iz for some c ∈ ℂ with |c| ≤ 1.
  2. f(z) = ceiz for some c ∈ ℂ with |c| ≤ 1.
  3. f(z) = e−ciz for some c ∈ ℂ with |c| ≤ 1.
  4. f(z) = eciz for some c ∈ ℂ with |c| ≤ 1.

Answer (Detailed Solution Below)

Option 1 : f(z) = ce−iz for some c ∈ ℂ with |c| ≤ 1.
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Detailed Solution

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Explanation:

f be an entire function that satisfies |f(z)| ≤ ey for all z = x + iy ∈ ℂ

(1): f(z) = ce−iz 

So |f(z)| = |ce−iz| = |ce-i(x + iy)| = |ce-ix ey| ≤ |c|ey ≤ ey for some c ∈ ℂ with |c| ≤ 1 (as |e-ix| ≤ 1 for all x ∈ )

Option (1) is correct

(2): f(z) = ceiz 

So |f(z)| = |ceiz| = |cei(x + iy)| = |ceix e-y| ≤ e-y for some c ∈ ℂ with |c| ≤ 1 (as |e-ix| ≤ 1 for all x ∈ )

Option (2) is false

(3): f(z) = e−ciz 

So |f(z)| = |e−ciz | = |e-ci(x + iy)| = |e-cix ecy| ≤ ecy ≤ ey for c = 1 only (as |e-ix| ≤ 1 for all x ∈ )

Option (3) is false

(4): f(z) = eciz 

So |f(z)| = |eciz | = |eci(x + iy)| = |ecix e-cy| ≤ e-cy ≤ ey for c = - 1 only (as |e-ix| ≤ 1 for all x ∈ )

Option (4) is false

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