In the given figure, a UDL load of 0.5 T/m is applied on the beam. Find the maximum positive shear force. 

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DDA JE Civil 29 Mar 2023 Shift 3 Official Paper
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  1. 15 T
  2. 4.625 T
  3. 5 T
  4. 7.5 T

Answer (Detailed Solution Below)

Option 2 : 4.625 T
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Detailed Solution

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Explanation:

To find the reactions of support A and B.

By equating the moment about B

So, 

Shear force calculation

Ffree = 0 T

FA(L) = -2.5 T

FA(R) = -2.5 + 7.125 = 4.625 T

FX(L) = 4.625 - (0.5 x 10) = -0.375 T

FX(R) = -0.375 T

FB(L) = -0.375 T

FB(R) = -0.375 + 0.375 = 0 T

So the maximum positive shear force is 4.625 T.

Additional Information The shear force diagram for the given problem is as follows.

 

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