Question
Download Solution PDFIf y = sec2 θ + cos2 θ, where
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Trigonometric Property :
Calculations:
Given, y = sec2 θ + cos2 θ, where
⇒ y = sec2 θ + cos2 θ - 2 + 2
⇒ y = sec2 θ - 2 sec θ cos θ + cos2 θ + 2
⇒ y = (sec - cos θ)2 + 2
As (sec - cos θ)2
⇒ (sec - cos θ)2 + 2
⇒ y ≥ 2
Hence, if y = sec2 θ + cos2 θ, where
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