If a, b, c are in geometric progression, then logax x, logbx x and logcx x are in

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NIMCET 2015 Official Paper
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  1. Arithmetic progression
  2. Geometric progression
  3. Harmonic progression
  4. Arithmetico-geometric progression

Answer (Detailed Solution Below)

Option 3 : Harmonic progression
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NIMCET 2020 Official Paper
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120 Questions 480 Marks 120 Mins

Detailed Solution

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Concept:

If a, b, c are in geometric progression then b2 = ac

If b - a = c - b, than a, b, c are in AP.

If 1/a, 1/b, 1/c are in AP than a, b, c are in HP.

\({\log _a}b = \frac{1}{{{{\log }_b}a}}\)

Calculation:

If a, b, c are in geometric progression then b2 = ac

So, by multiplying both side by x2 and taking log on both side to the base x

\({\log _x}({x^2}{b^2}) = {\log _x}({x^2}ac)\)

\({\log _x}({x^2}{b^2}) = {\log _x}(xa\cdot xc)\)

\(2{\log _x}xb = {\log _x}xa + {\log _x}xc\)

\({\log _x}xb - {\log _x}xa = {\log _x}xc - {\log _x}xb\)

so logx ax, logx bx and logx cx are in AP.

\(\frac{1}{{{{\log }_{ax}}x}},\frac{1}{{{{\log }_{bx}}x}},\frac{1}{{{{\log }_{cx}}x}}\) are also in AP

\({\log _{ax}}x,{\log _{bx}}x,{\log _{cx}}x\) are in HP

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