Identify the CORRECT statement about Simply Supported beam.

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Question

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JKSSB JE CE 2021 Official Paper Shift 2 (Held on 29 Oct 2021)

Answer 1

Explanation:

Case 1:

For a simply supported beam of length (L) loaded with uniform loading intensity (w):

Load P is distributed over length l. hence, UDL = w/length
where P = w × l and length is the same for both the beams (i.e. L = l).
Maximum shear force is\( F = {w\times L\over 2}={P\over 2} \)
Maximum bending moment is \(M_{UDL}={w×L^2\over 8}={P\times L\over 8}\)......................(2)

F1 N.M D.K 13.08.2019 D 4

Case 2:

For a simply supported beam of length (L) loaded with Point load P.

From the above both diagrams, in simply supported beam, at the supports, the BM is zero and Shear Force is maximum.