Identify the CORRECT statement about Simply Supported beam.

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JKSSB JE CE 2021 Official Paper Shift 2 (Held on 29 Oct 2021)
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  1. BM – Max at supports, SF – Zero at supports
  2. BM – Zero at supports, SF – Zero at supports
  3. BM – Max at supports, SF – Max at supports
  4. BM – Zero at supports, SF – Max at supports

Answer (Detailed Solution Below)

Option 4 : BM – Zero at supports, SF – Max at supports
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Detailed Solution

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Explanation:

Case 1:

For a simply supported beam of length (L) loaded with uniform loading intensity (w):

  • Load P is distributed over length l. hence, UDL = w/length
  • where P = w × l and length is the same for both the beams (i.e. L = l).
  • Maximum shear force is\( F = {w\times L\over 2}={P\over 2} \)
  • Maximum bending moment is \(M_{UDL}={w×L^2\over 8}={P\times L\over 8}\)......................(2)

F1 N.M D.K 13.08.2019 D 4

Case 2:

For a simply supported beam of length (L) loaded with Point load P.

  • Maximum shear force is \( F ={P\over 2} \) 
  • The maximum bending moment will develop at the mid-point (M).
  • Maximum bending moment is \(M={P× L\over 4}\)........................(1)

From the above both diagrams, in simply supported beam, at the supports, the BM is zero and Shear Force is maximum. 

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