How the Potential energy (E) of a particle executing simple harmonic motion varies according to displacement x from mean position?

  1. E ∝ x
  2. E ∝ x2
  3. E ∝ 1/x
  4. Potential energy is constant and does not change with displacement

Answer (Detailed Solution Below)

Option 2 : E ∝ x2
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Detailed Solution

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CONCEPT:

  • Simple harmonic motion occurs when the restoring force or acceleration is directly proportional to the displacement from equilibrium or mean position.

F α -x

Where F = force and x = the displacement from equilibrium.

  • Potential Energy of a body performing SHM:

\(E=\frac{1}{2}mω^2 x^2\)

where m is the mass of the body, ω is the angular frequency, and x is the position with respect to time.

EXPLANATION:

Potential Energy of a particle

\(E=\frac{1}{2}mω^2 x^2\)

So E ∝ x2

The correct answer is option 2.

Additional informaion

  • The kinetic energy of a particle executing SHM is given by:

\(KE=\frac{1}{2}mv^2=\frac{1}{2}m\omega^2(A^2-x^2)\)

  • Total Energy of the particle

Total energy = K.E. + P.E.

\(E=\frac{1}{2}mω^2 A^2\)

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