Question
Download Solution PDFE = 2 × 105 N/mm2 से 2000 mm व्यास की 10 mm व्यास वाली इस्पात छड़ के बंकन में विकसित प्रतिबल क्या है?
Answer (Detailed Solution Below)
Detailed Solution
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बंकन प्रतिबल की गणना निम्न द्वारा की जा सकती है
जहाँ σb = बंकन प्रतिबल, E = प्रत्यास्थता का यंग मापांक, I = अनुप्रस्थ काट का जड़त्व आघूर्ण, R = वक्रता त्रिज्या, y = उदासीन अक्ष से बाहरी फाइबर की दूरी
गणना:
दिया हुआ:
छड़ का व्यास (d) = 10 mm, वक्रता व्यास (d) = 2000 mm, E = 2 × 105 N/mm2
वक्रता त्रिज्या,
σb = 1000 N/mm2
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