2.5 से मापे गए अवलोकनों की n संख्या के विचलनों का योग 50 है। 3.5 से मापे गए अवलोकनों के समान सेट के विचलनों का योग -50 है। n का मान क्या है?

This question was previously asked in
NDA (Held On: 6 Sep 2020) Maths Previous Year paper
View all NDA Papers >
  1. 50
  2. 60
  3. 80
  4. 100

Answer (Detailed Solution Below)

Option 4 : 100
Free
NDA 01/2025: English Subject Test
5.6 K Users
30 Questions 120 Marks 30 Mins

Detailed Solution

Download Solution PDF

संकल्पना:

विचलन = |डेटा मान - माध्य|

 

गणना:

मान लें, डेटा मान a1,a2,a3,....,an है

(a12.5)+(a22.5)+(a32.5)++(an2.5)=50

(a1+a2+a3+.....+an)2.5(n)=50

(a1+a2+a3+.....+an)=50+2.5n and 

(a13.5)+(a23.5)+(an3.5)=50

(a1+a2+a3+.....+an)3.5(n)=50

(a1+a2+a3+.....+an)=50+3.5n

Now,

अब -50 + 3.5n = 50 + 2.5n

⇒n = 100

⇒ n = 100

इसलिए, विकल्प (4) सही है।

Latest NDA Updates

Last updated on Jun 18, 2025

->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.

-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.

->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.

-> The selection process for the NDA exam includes a Written Exam and SSB Interview.

-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100. 

-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential. 

More Statistics Questions

Get Free Access Now
Hot Links: teen patti gold apk teen patti bliss teen patti master king teen patti 100 bonus