Question
Download Solution PDFसिग्नल x(t) = 2 cos (2000 πt) cos (5000 πt) के लिए नाइक्विस्ट दर क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
नाइक्विस्ट दर वह न्यूनतम दर है जिसपर एक सिग्नल को किसी त्रुटियों को पेश किये बिना प्रतिरूपित किया जा सकता है, जो सिग्नल में मौजूद उच्चतम आवृत्ति का दोगुना होता है।
नाइक्विस्ट दर = 2 × सिग्नल में मौजूद उच्चतम आवृत्ति
fs = 2fm
गणना:
ω1 = 3000 π ⇒ f1 = 1500 Hz
ω2 = 7000 π ⇒ f2 = 3500 Hz
fm = max (f1, f2) = 3500 Hz
नाइक्विस्ट दर, fs = 2fm = 2 × 3500 = 7 kHz
Last updated on Jul 2, 2025
-> ESE Mains 2025 exam date has been released. As per the schedule, UPSC IES Mains exam 2025 will be conducted on August 10.
-> UPSC ESE result 2025 has been released. Candidates can download the ESE prelims result PDF from here.
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.