Question
Download Solution PDFसदिश A = 3i + 5j - 4k और B = -5i + 11j + 10k के बीच का कोण क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
दो सदिश A और B के बीच कोण θ को निम्न द्वारा ज्ञात किया गया है:
cos θ = \(\rm \vec A\cdot\vec B\over|\vec A||\vec B|\)
गणना:
दिया गया है A = 3i + 5j - 4k और B = -5i + 11j + 10k
माना कि उनके बीच का कोण θ है।
cos θ = \(\rm (3i+5j-4k)\cdot(-5i+11j+10k)\over\sqrt{(3)^2+(5)^2+(-4)^2} \times\sqrt{(5)^2+(11)^2+(10)^2}\)
cos θ = \(\rm (-15+55-40)\over\sqrt{50} \times\sqrt{246}\)
cos θ = 0
∴ θ = \(\boldsymbol{\pi\over2}\)
Last updated on May 26, 2025
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