Question
Download Solution PDFएक 4 ध्रुव, 20 kW, 200 V वाले तरंग कुंडलित DC शंट जनरेटर में प्रत्येक समानांतर पथ में धारा _________होगी।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
प्रत्येक समानांतर पथ में धारा
A समानांतर पथों की संख्या है
एक तरंग कुंडलित जनरेटर में समानांतर पथों की संख्या = 2
एक लैप कुंडलित जनरेटर में समानांतर पथों की संख्या = ध्रुवों की संख्या
गणना:
शक्ति (P) = 20 kW
वोल्टेज (V) = 200 V
कुल धारा
समानांतर पथों की संख्या = 2
प्रत्येक समानांतर पथ में धारा
Last updated on Jul 1, 2025
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