यदि \(\rm \vec{a},\vec{b},\vec{c}\) तीन गैर-समतलीय सदिश हैं, तो \(\rm (\vec{a}+\vec{b}+\vec{c}) \cdot[(\vec{a}+\vec{b}) \times( \vec{a}+\vec{c})]=\) का मान क्या है?

This question was previously asked in
NIMCET 2020 Official Paper
View all NIMCET Papers >
  1. 0
  2. \(\rm [\vec{a}\; \vec{b} \;\vec{c}]\)
  3. 2\(\rm [\vec{a}\; \vec{b} \;\vec{c}]\)
  4. -\(\rm [\vec{a}\; \vec{b} \;\vec{c}]\)

Answer (Detailed Solution Below)

Option 4 : -\(\rm [\vec{a}\; \vec{b} \;\vec{c}]\)
Free
NIMCET 2020 Official Paper
10.7 K Users
120 Questions 480 Marks 120 Mins

Detailed Solution

Download Solution PDF

संकल्पना:

यदि \(\rm \vec P, \vec Q, \vec R\) सदिश हैं, तो 

  • \(\rm \vec P \times \vec P = 0\)
  • \(\rm \vec P\cdot(\rm \vec P \times \text{any vector}) =0\)
  • \(\rm \vec P\cdot (\vec Q\times\vec R) = \vec Q\cdot (\vec R\times\vec P)=\vec R\cdot( \vec P\times\vec Q) =[ \vec P, \vec Q, \vec R]\)
  • बिंदु गुणनफल के लिए \(\rm (\vec P + \vec Q) \cdot \vec R = (\vec P\cdot \vec R) +(\vec Q\cdot \vec R)\)
  • पार गुणनफल के लिए \(\rm (\vec P + \vec Q) \times\vec R = (\vec P\times\vec R) + (\vec Q\times\vec R) \)

 

गणना:

 \(\rm S=(\vec{a}+\vec{b}+\vec{c}) \cdot[(\vec{a}+\vec{b}) \times( \vec{a}+\vec{c})]\)

⇒ \(\rm S=(\vec{a}+\vec{b}+\vec{c}) \cdot[(\vec{a}\times\vec{a}+\vec{a}\times\vec{c}+\vec{b}\times\vec{a}+\vec{b}\times\vec{c})]\)

⇒ \(\rm S=(\vec{a}+\vec{b}+\vec{c}) \cdot[(0+\vec{a}\times\vec{c}+\vec{b}\times\vec{a}+\vec{b}\times\vec{c})]\)

⇒ \(\rm S=\vec{a}\cdot[\vec{a}\times\vec{c}+\vec{b}\times\vec{a}+\vec{b}\times\vec{c}]+\vec{b}\cdot[\vec{a}\times\vec{c}+\vec{b}\times\vec{a}+\vec{b}\times\vec{c}]+\vec{c}\cdot[\vec{a}\times\vec{c}+\vec{b}\times\vec{a}+\vec{b}\times\vec{c}] \)

⇒ \(\rm S=\vec{a}\cdot(\vec{a}\times\vec{c})+\vec{a}\cdot(\vec{b}\times\vec{a})+\vec{a}\cdot(\vec{b}\times\vec{c})+\vec{b}\cdot(\vec{a}\times\vec{c})+\vec{b}\cdot(\vec{b}\times\vec{a})+\vec{b}\cdot(\vec{b}\times\vec{c})+\vec{c}\cdot(\vec{a}\times\vec{c})+\vec{c}\cdot(\vec{b}\times\vec{a})+\vec{c}\cdot(\vec{b}\times\vec{c})\)

⇒ \(\rm S=0+0+\vec{a}\cdot(\vec{b}\times\vec{c})+\vec{b}\cdot(\vec{a}\times\vec{c})+0+0+0+\vec{c}\cdot(\vec{b}\times\vec{a})+0\)

⇒ \(\rm S=\vec{a}\cdot(\vec{b}\times\vec{c})+\vec{b}\cdot(\vec{a}\times\vec{c})+\vec{c}\cdot(\vec{b}\times\vec{a}) \)

⇒ \(\rm S=\vec{a}\cdot(\vec{b}\times\vec{c})+\boldsymbol{\rm [-\vec{b}\cdot(\vec{c}\times\vec{a})]+[-\vec{c}\cdot(\vec{a}\times\vec{b})]}\)

⇒ \(\rm S=[\vec{a}, \vec{b}, \vec{c}]-[\vec{a}, \vec{b}, \vec{c}]-[\vec{a}, \vec{b}, \vec{c}]\)

 \(\boldsymbol{\rm S=-[\vec{a}, \vec{b}, \vec{c}]}\)

Latest NIMCET Updates

Last updated on Jun 12, 2025

->The NIMCET 2025 provisional answer key is out now. Candidates can log in to the official website to check their responses and submit objections, if any till June 13, 2025.

-> NIMCET exam was conducted on June 8, 2025.

-> NIMCET 2025 admit card was out on June 3, 2025.

-> NIMCET 2025 results will be declared on June 27, 2025. Candidates are advised to keep their login details ready to check their scrores as soon as the result is out.

-> Check NIMCET 2025 previous year papers to know the exam pattern and improve your preparation.

More Scalar Triple Product Questions

More Vector Algebra Questions

Get Free Access Now
Hot Links: teen patti party teen patti rummy teen patti royal - 3 patti