Question
Download Solution PDF80% दक्ष, 2kW (इनपुट) मोटर अधिकतम भार पर 5 घण्टे से चल रही है तो उसके द्वारा उपयोग की गई ऊर्जा कितनी होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
दक्षता(η) = (आउटपुट शक्ति)/(इनपुट शक्ति)
ऊर्जा = (शक्ति) (समय)
गणना:
आउटपुट शक्ति = (इनपुट शक्ति) (दक्षता) = 2 x 0.8
आउटपुट शक्ति = 1.6 kW
आउटपुट ऊर्जा = 1.6 x 5 = 8 kWhLast updated on Jun 26, 2025
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