Question
Download Solution PDFयदि logx 4 + logx 16 + logx 64 = 12 तो x का मान ज्ञात कीजिए
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया है:
logx 4 + logx 16 + logx 64 = 12
प्रयुक्त सूत्र:
यदि logx y = a, तो xa = y
logx ab = b logx a
गणना:
logx 4 + logx 16 + logx 64 = 12
⇒ logx 22 + logx 24 + logx 26 = 12
⇒ 2 logx 2 + 4 logx 2 + 6 logx 2 = 12
⇒ 12 logx 2 = 12
⇒ logx 2 = 1
⇒ 2 = x1
∴ x = 2
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