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(x - a)2 + (y - b)2 + z2 = c2

से a और b को हटाने पर आंशिक अवकल समीकरण क्या है?

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  1. z2(p - q + 1) = c2
  2. z2(p2 + q2 + 1) = c2
  3. z2(p2 + q2) = c2
  4. z2(p - q) = c2

Answer (Detailed Solution Below)

Option 2 : z2(p2 + q2 + 1) = c2
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Detailed Solution

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व्याख्या:

(x - a)2 + (y – b)2 + z2 = c2         ---(i)

'x' के सापेक्ष 

(i) का अवकलन करने पर

जब,

'y' के सापेक्ष (i) का अवकलन करने पर

(-zp)2 + (-zq)2 + z2 = c2

z2 (p2 + q2 + 1) = c2

 ∴ विकल्प (2) सही है। 

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