Question
Download Solution PDFएक आयाम मॉडूलित सिग्नल में 10 kHz की वाहक आवृत्ति होती है। ऊपरी साइडबैंड 11 kHz पर संचरित होता है। AM सिग्नल को संचारित करने के लिए आवश्यक बैंडविड्थ __________ है
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
एक आयाम माॅडुलित तरंग का आवृत्ति स्पेक्ट्रम निम्न द्वारा दिया गया है:
AM में बैंडविड्थ = (fc + fm) - (fc - fm)
AM में बैंडविड्थ = 2fm
गणना:
fc = 10 kHz
ऊपरी साइडबैंड = fc + fm = 11 kHz
∴ संदेश आवृत्ति इस प्रकार है:
fm = 11 – 10 = 1 kHz
इसलिए, बैंडविड्थ इस प्रकार है:
= 2fm = 2 × 1 kHz = 2 kHz
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