एक गतिपालक चक्र का वजन \(\frac{{981}}{\pi }\) kgf होता है और इसकी त्रिज्या 100 cm होती है। इसकी क्षैतिज धुरी के बारे में इसे 100 r.p.m. का प्रचक्रण दिया जाता है। पूरी असेंबली एक ऊर्ध्वाधर अक्ष के बारे में 6 rad/s पर घूर्णन कर रही है। अनुभवी घूर्णाक्षस्थापी युग्म _____ होगा।

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ESE Mechanical 2018 Official Paper
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  1. 2000 kgf-m
  2. 1962 kgf-m
  3. 200 kgf-m
  4. 196 kgf-m

Answer (Detailed Solution Below)

Option 1 : 2000 kgf-m
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ST 1: UPSC ESE (IES) Civil - Building Materials
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Detailed Solution

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संकल्पना:

घूर्णाक्षस्थापी युग्म = I × ω × ωp

जहां I गतिपालक चक्र का जड़त्व आघूर्ण है, ωp प्रचक्रण का कोणीय वेग है और ω गतिपालक चक्र की घूर्णन गति है

गणना:

दिया गया है, W = \(\frac{{981}}{\pi }\) kgf ⇒ m = \(\frac{{981}}{\pi }\) kg, परिचलन की त्रिज्या k = 100 cm = 1m, = 6rad/s, N = 100 rpm,

\(I = m{k^2} = \frac{{981}}{{\pi }} × {\left( 1 \right)^2}\) kg-m2

\(I = \frac{{981}}{\pi }\;kg-\;{m^2}\)

\(ω_p = \frac{{2\pi N}}{{60}} = \frac{{2\pi × 100}}{{60}} = \frac{{20\pi }}{6}\;rad/sec\)

\(T = Iω \;{ω _p} = \frac{{981}}{\pi } × \frac{{20\pi }}{6} × 6= 19620 \ kg \ m^2/s^2 = 19620\;Nm\)

1 kgf = 9.81 N

⇒ T = 2000 kgf-m

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