Question
Download Solution PDFचित्र में दिखाए गए परिपथ के बिंदु A और B के बीच 50 V की एक नियत वोल्टता पर रखा जाता है। परिपथ की शाखा CD से गुजरने वाली धारा है:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसही विकल्प: (2) 2.0 A है।
RAB = (1Ω / 3Ω) श्रेणीक्रम में (2Ω / 4Ω) के साथ
⇒ (1 × 3) / (1 + 3) + (2 × 4) / (2 + 4)
= 3 / 4 + 8 / 6 = (9 + 16) / 12 = 25 / 12 Ω
अब सेल से कुल धारा
I = 50 / (25 / 12) = 24 A
I1Ω = (3 / 4) × 24 = 18 A, I3Ω = (1 / 4) × 24 = 6 A
I2Ω = (4 / 6) × 24 = 16 A, I4Ω = (2 / 6) × 24 = 8 A
संधि नियम C पर प्रयोग करने पर,
ICD = 18 − 16 = 2 A (C से D तक)
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