एक वस्तु 200 MPa के साधारण अपरूपण प्रतिबल के साथ एक तल में 300 MPa के प्रत्यक्ष तन्य प्रतिबल के अधीन है। तो तल पर अधिकतम सामान्य प्रतिबल क्या होगा?

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  1. 100 MPa
  2. 200 MPa
  3. 300 MPa
  4. 400 MPa

Answer (Detailed Solution Below)

Option 4 : 400 MPa
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Detailed Solution

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संकल्पना:

अधिकतम और न्यूनतम सामान्य प्रतिबल को निम्न द्वारा ज्ञात किया गया है

\({\sigma _{max,\;\;min}} = \frac{{{\sigma _x} + {\sigma _y}}}{2}\; \pm \sqrt {{{\left( {\frac{{{\sigma _x}\; - \;{\sigma _y}}}{2}} \right)}^2} + \tau _{xy}^2} \)

जहाँ, σx और σy प्रत्यक्ष प्रतिबल हैं और τxy अपरूपण प्रतिबल है। 

गणना:

दिया गया है, प्रत्यक्ष प्रतिबल σx = 300 MPa, τxy = 200 MPa

अब अधिकतम सामान्य प्रतिबल 

\({\sigma _{max}} = \frac{{{\sigma _x} + {\sigma _y}}}{2} + \sqrt {{{\left( {\frac{{{\sigma _x}\; - \;{\sigma _y}}}{2}} \right)}^2} + \tau _{xy}^2} \)

\({\sigma _{max}} = \frac{{300}}{2} + \sqrt {{{\left( {\frac{{300}}{2}} \right)}^2} + {{200}^2}} = 400\;MPa\)

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