Question
Download Solution PDFFrom point H, at 6 : 30 pm, a train starts moving towards point K at the speed of 90 km/hr. Another train starts moving from point K at 7 : 30 p.m. towards point H at the speed of 72 km/hr. Both the train meet at 11 : 30 p.m. at point J. What is the ratio of the distance HJ and KJ?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Speed of train A is 90 km/h moving from H to K at 6:30 pm
Speed of train B is 72 km/h moving from K to H at 7:30 pm
Both train meet at 11:30 pm
Formula used:
Distance = Speed × Time
Calculations:
Total time travel by train A is from 6:30 pm to 11:30 pm
⇒ Total time = 5 h
⇒ Distance travel by Train A = Speed × Time = 90 × 5 = 450 km
Total time travel by train B is from 7:30 pm to 11:30 pm
⇒ Total time = 4 h
⇒ Distance travel by Train B = Speed × Time = 72 × 4 = 288 km
Ratio of Distance travel by train A and train B
⇒ Train A : Train B = 450 : 288 = 25 : 16
⇒ Hence, The ratio of distance traveled by train A and train B is 25 : 16
Last updated on Jul 17, 2025
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