For a two port network to be reciprocal: 

This question was previously asked in
JKSSB JE Electrical 2015 Official Paper
View all JKSSB JE Papers >
  1. Z11= Z22
  2. Y21 = Y21
  3. h21 = h22
  4. AD-BC = 0 

Answer (Detailed Solution Below)

Option 4 : AD-BC = 0 
Free
JKSSB JE Civil RCC Structures Mock Test
1.2 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

Explanation:

Reciprocity in Two-Port Networks

Definition: A two-port network is said to be reciprocal if the transfer of signal or energy between port 1 and port 2 is the same in either direction under the same conditions. Reciprocity is a property often associated with linear passive networks and is crucial in the design of electrical systems such as filters, amplifiers, and communication networks. Mathematically, this property ensures that the forward and reverse transmission characteristics are identical under certain conditions.

Conditions for Reciprocity: Reciprocity of a two-port network can be analyzed using different network parameters such as impedance (Z), admittance (Y), hybrid (h), and transmission (ABCD) parameters. The condition for reciprocity varies depending on the type of network parameters being used. Here’s a breakdown:

  • Impedance Parameters (Z): For the network to be reciprocal using Z-parameters, the condition is Z12 = Z21.
  • Admittance Parameters (Y): For the network to be reciprocal using Y-parameters, the condition is Y12 = Y21.
  • Hybrid Parameters (h): For the network to be reciprocal using h-parameters, the condition is h12 = -h21.
  • Transmission Parameters (ABCD): For the network to be reciprocal using ABCD parameters, the condition is AD - BC = 1.

Correct Option Analysis:

The correct option is:

Option 4: AD - BC = 1

This condition pertains to the transmission (ABCD) parameters of a two-port network. The ABCD parameters, also known as transmission parameters, describe the input and output voltages and currents of the two-port network. They are expressed as:

V1 = AV2 + BI2

I1 = CV2 + DI2

Here, A, B, C, and D are the transmission parameters. For a network to be reciprocal, the determinant of the ABCD parameter matrix must equal 1, i.e.,:

AD - BC = 1

This means that the energy transfer between port 1 and port 2 is identical in both directions, confirming reciprocity. This condition is widely used in the analysis of transmission lines, filters, and communication systems to ensure symmetry in signal transmission.

Additional Information

To further understand the analysis, let’s evaluate the other options:

Option 1: Z11 = Z22

This option is incorrect. The condition Z11 = Z22 does not imply reciprocity in a two-port network. Instead, it suggests symmetry in the impedance parameters. Reciprocity in Z-parameters is defined by the condition Z12 = Z21.

Option 2: Y21 = Y21

This option is incorrect and is a typographical error. The correct condition for reciprocity in terms of Y-parameters is Y12 = Y21. This ensures that the admittance between the two ports is identical in both directions.

Option 3: h21 = h22

This option is incorrect. The condition h21 = h22 does not imply reciprocity in a two-port network. Reciprocity in terms of h-parameters is defined by the condition h12 = -h21, which involves a specific relationship between the forward and reverse hybrid parameters.

Option 5: No option is mentioned for Option 5, so it is irrelevant to the problem.

Conclusion:

Understanding the concept of reciprocity in two-port networks is vital for analyzing and designing electrical systems. The correct condition for reciprocity depends on the type of network parameters being used. In this case, the transmission (ABCD) parameters define reciprocity with the condition AD - BC = 1. This ensures symmetry in energy transfer between ports, making the network reciprocal. By analyzing the incorrect options, we see that they either misrepresent the reciprocity condition or describe different properties of the network parameters.

Latest JKSSB JE Updates

Last updated on Jul 1, 2025

-> JKSSB Junior Engineer recruitment exam date 2025 for Civil and Electrical Engineering has been rescheduled on its official website. 

-> JKSSB JE exam will be conducted on 31st August (Civil), and on 24th August 2025 (Electrical).

-> JKSSB JE application form correction facility has been started. Candidates can make corrections in the JKSSB recruitment 2025 form from June 23 to 27. 

-> JKSSB JE recruitment 2025 notification has been released for Civil Engineering. 

-> A total of 508 vacancies has been announced for JKSSB JE Civil Engineering recruitment 2025. 

-> JKSSB JE Online Application form will be activated from 18th May 2025 to 16th June 2025 

-> Candidates who are preparing for the exam can access the JKSSB JE syllabus PDF from official website of JKSSB.

-> The candidates can check the JKSSB JE Previous Year Papers to understand the difficulty level of the exam.

-> Candidates also attempt the JKSSB JE Mock Test which gives you an experience of the actual exam.

Get Free Access Now
Hot Links: teen patti glory teen patti download teen patti octro 3 patti rummy