Find a vector perpendicular to the plane that passes through the points P(1, 4, 6), Q(-2, 5, -1) and R(1, -1, 1).

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AAI ATC Junior Executive 27 July 2022 Shift 1 Official Paper
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  1. (-40, -15, 15)
  2. (7, 4, -2)
  3. (40, -15, 15)
  4. (-40, -18, 15)

Answer (Detailed Solution Below)

Option 1 : (-40, -15, 15)
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Detailed Solution

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Concept:

To find a vector perpendicular to the find two planes, first, find the vector in the plane and then take their cross product.

Solution:

Given, the plane is passing through the points P(1, 4, 6), Q(-2, 5, -1) and R(1, -1, 1).

Step (1) Find two vectors in the plane.

We will do this by finding the vector from (1, 4, 6) (-2, 5, -1) and (1, 4, 6) (1, -1, 1).

As all three points are in the plane, so will each of those vectors.

Step (2) Find a vector perpendicular to the plane.

If a vector is perpendicular to two vectors in a plane, it must be perpendicular to the plane itself. As the cross-product of two vectors produces a vector perpendicular to both, we will use the cross-product of   to find a vector  perpendicular to the plane containing them.

Hence, the vector perpendicular to the plane that passes through the points P(1, 4, 6), Q(-2, 5, -1), and R(1, -1, 1) is (-40, -15, 15).

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