Calculate Young's Modulus of Elasticity of a material, whose bulk modulus is 50 GPa, modulus of rigidity is 30 GPa and Poisson's ratio is 0.25.

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DDA JE Civil 01 Apr 2023 Shift 3 Official Paper
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  1. 75 GPa
  2. 110 GPa
  3. 60 GPa
  4. 90 GPa

Answer (Detailed Solution Below)

Option 1 : 75 GPa
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Detailed Solution

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Concept :

The relation between E, K, and μ

E = 2G (1 + μ)

E = 3K (1 - 2μ)

\({\rm{E}} = \frac{{9{\rm{KG}}}}{{3{\rm{K}} + {\rm{G}}}}\)

Where,

E = Young's Modulus of Rigidity = Stress / strain

G = Shear Modulus or Modulus of rigidity = Shear stress / Shear strain = 30 GPa

μ = Poisson’s ratio = - lateral strain / longitudinal strain

K = Bulk Modulus of elasticity = Volumetric stress / Volumetric strain = 50 GPa

Calculation:

\({\rm{E}} = \frac{{9{\rm{KG}}}}{{3{\rm{K}} + {\rm{G}}}}\)

\({\rm{E}} = \frac{{9{\rm{\times 50 \times 30}}}}{{3{\rm{\times 50}} + {\rm{30}}}}\)

E = 75 GPa

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