An electron has a constant acceleration of +3.2 m/s2. At a certain instant its velocity is +9.6 m/s. The velocity of the electron 2.5 s earlier was

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ISRO VSSC Technical Assistant Mechanical 9 June 2019 Official Paper
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  1. +3.6 m/s
  2. +1.6 m/s
  3. +2.4 m/s
  4. +1.9 m/s

Answer (Detailed Solution Below)

Option 2 : +1.6 m/s
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Detailed Solution

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Concept:

Using equation of motion,

v = u + at

where v = final velocity, u = initial velocity, a = acceleration, t = time

Calculation:

Given:

v = 9.6 m/s, a = 3.2 m/s2, t = 2.5 s

v = u + at

9.6 = u + (3.2 × 2.5)

∴ u = 9.6 - 8 = 1.6 m/s

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