Question
Download Solution PDFAn electron has a constant acceleration of +3.2 m/s2. At a certain instant its velocity is +9.6 m/s. The velocity of the electron 2.5 s earlier was
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Using equation of motion,
v = u + at
where v = final velocity, u = initial velocity, a = acceleration, t = time
Calculation:
Given:
v = 9.6 m/s, a = 3.2 m/s2, t = 2.5 s
v = u + at
9.6 = u + (3.2 × 2.5)
∴ u = 9.6 - 8 = 1.6 m/s
Last updated on May 30, 2025
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