Question
Download Solution PDFA stream of water flowing horizontally with a speed of 20 m/s pushes out of a tube of cross-sectional area 10-1m2 and hits at a vertical wall nearby. Find the force exerted on the wall by the impact of water, assuming that it does not rebound?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Speed of stream of water (v) = 20 m/s
Area of cross-section of tube (A)= 10-1m2 (or 0.1 m2)
Concept:
Force exerted on the wall = Rate of loss in momentum of the water
Formula:
The volume rate of flow of water: dV/dt = Av
The mass rate of flow of water: dm/dt = ρAv
Rate of loss in momentum of water = (dm/dt)v
Calculation:
Mass rate of flow of water : dm/dt = ρAv
⇒ dm/dt = 1000 × 0.1 × 20
= 2000 kg/s
Rate of loss in momentum of water = (dm/dt)v
⇒ (dm/dt)v = 2000 × 20
= 40000 N
∴ Force exerted = 40000 N
Last updated on Jun 19, 2025
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