A solenoid of length 1.5 m and 4 cm diameter possesses 10 turns per cm. A current of 5A is flowing through it, the magnetic induction at axis inside the solenoid is

(μ0 = 4π × 10-7 weber amp-1 m-1)

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  1. 4π × 10-7 gauss
  2. 2π × 10-7 gauss
  3. 4π × 10-5 tesla
  4. 2π × 10-5 tesla

Answer (Detailed Solution Below)

Option 4 : 2π × 10-5 tesla
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Detailed Solution

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Calculation:
The magnetic field inside a solenoid is given by the formula:

B = μ₀ × n × I

Where:

  • μ₀ = 4π × 10-7 weber amp-1 m-1 (permeability of free space)
  • n = number of turns per unit length = 10 turns per cm = 10 × 102 turns/m
  • I = current passing through the solenoid = 5A

Now, substituting the values into the equation:

B = (4π × 10-7) × (10 × 102) × 5

B = 2π × 10-5 tesla

The magnetic induction at the axis inside the solenoid is 2π × 10-5 tesla.

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