Question
Download Solution PDFA solenoid of length 1.5 m and 4 cm diameter possesses 10 turns per cm. A current of 5A is flowing through it, the magnetic induction at axis inside the solenoid is
(μ0 = 4π × 10-7 weber amp-1 m-1)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
The magnetic field inside a solenoid is given by the formula:
B = μ₀ × n × I
Where:
- μ₀ = 4π × 10-7 weber amp-1 m-1 (permeability of free space)
- n = number of turns per unit length = 10 turns per cm = 10 × 102 turns/m
- I = current passing through the solenoid = 5A
Now, substituting the values into the equation:
B = (4π × 10-7) × (10 × 102) × 5
B = 2π × 10-5 tesla
The magnetic induction at the axis inside the solenoid is 2π × 10-5 tesla.
Last updated on Jun 6, 2025
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