A single rolling load of 40 kN rolls from left end along a simply supported girder of span 20 m. The absolute maximum positive and negative shear force, respectively are:

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SSC JE CE Previous Year Paper 10 (Held on 30 Oct 2020 Evening)
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  1. 14 kNand -26 kN
  2. 40 kN and -40 kN
  3. 26 kN and -14 kN
  4. 20 kN and -20 kN

Answer (Detailed Solution Below)

Option 2 : 40 kN and -40 kN
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Detailed Solution

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Concept:

Influence line diagram:

An influence line for a given function, such as a reaction, axial force, shear force, or bending moment, is a graph that shows the variation of that function at any given point on a structure due to the application of a unit load at any point on the structure. ILD can be drawn for statically determinate as well as indeterminate structures.

Advantages of drawing ILD are as follows:

i) To determine the value of a quantity (shear force, bending moment, deflection, etc.) for a given system of loads on the span of the structure.

ii) To determine the position of a live load for the quantity to have the maximum value and hence to compute the maximum value of the quantity.

Explanation:

F1 Abhishek M 1.3.21 Pallavi D4

Rolling load = 40 kN

Maximum positive shear force:

F1 Abhishek M 1.3.21 Pallavi D5

When rolling load will be acting at point A then the shear force will be maximum.

Maximum shear force = Magnitude of load × ordinate of ILD under the load

= 40 × 1 = 40 kN (+)

Maximum negative shear force:

F1 Abhishek M 1.3.21 Pallavi D6

When rolling load will be acting at point B then the shear force will be maximum.

Maximum shear force = Magnitude of load × ordinate of ILD under the load

= 40 × 1 = 40 kN (-).

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