A person boarded an express train on 30th August 2015 at Ahmedabad for Trivandrum. The train departed from Ahmedabad at 13:30 hours and reached Trivandrum at 7:30 hours on 1st September 2015. If the distance between Ahmedabad and Trivandrum is 2268 km, the average speed of the train between the two stations was

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CTET Sep 2015 Paper 1 (L - I/II: Hindi/English)
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  1. 54 km/hr
  2. 42 km/hr
  3. 15 km/hr
  4. 9 km/hr

Answer (Detailed Solution Below)

Option 1 : 54 km/hr
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Concept:  
  • Speed = Distance/Time
  • Average Speed = (Total distance covered / Total time taken)

Given:

  • Time is given in 24hrs format.
  • Train departure time from Ahmedabad: 30th August, 13:30 hours.
  • Arrival time of the train at Trivandrum: 1st September, 7:30 hours.
  • The distance between Ahmedabad and Trivandrum is 2268 km.

Explanation:

Time is taken for the complete journey:

  • From 30th August, 13:30 hours to 31st August, 13:30 hours = 24 hours
  • From 31st August, 13:30 hours to 1st September, 1:30 hours = 12 hours
  • From 1st September, 1:30 hours to 1st September, 7:30 hours = 6 hours
  • Total time is taken = 42 hours

Average Speed = (Total distance covered / Total time taken) = 2268 km/42 hrs = 54 km/hr

Thus, the average speed of the bus during the entire journey is 54 km/hr.

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