A model of a hydraulic turbine is tested at a head of 1/4th of that under which the full scale turbine works. The diameter of the model is half of that of the full scale turbine. If N is the RPM of the full scale turbine, then the RPM of the model will be

  1. N/4
  2. N/2
  3. N
  4. 2N

Answer (Detailed Solution Below)

Option 3 : N
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Detailed Solution

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From similitude

\({\left( {\frac{{gH}}{{{N^2}{D^2}}}} \right)_{Model}} = {\left( {\frac{{gH}}{{{N^2}{D^2}}}} \right)_{actual}}\)

∴ Given Hmodel = H/4

Dmodel = D/2

\(\Rightarrow \frac{{\frac{{gH}}{4}}}{{N_{model}^2{{\left( {\frac{D}{2}} \right)}^2}}} = \frac{{gH}}{{{N^2}{D^2}}} \Rightarrow {N_{actual}} = {N_{model}}\)

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