A microprocessor based system uses 2K × 8 bits RAM with starting address CC00. The last address of byte in this RAM is

Explanation:

1. Understanding the Memory Size:

The size of the RAM is specified as 2K × 8 bits. This means the RAM has 2K memory locations, where each location can store 8 bits (1 byte) of data. The total number of memory addresses in this RAM is:

2K = 2 × 1024 = 2048 addresses.

2. Starting Address:

The RAM's starting address is CC00 (in hexadecimal format).

3. Calculating the Last Address:

To determine the last address, we add the total number of addresses (2048) to the starting address (CC00) and subtract 1. This subtraction is necessary because the starting address is inclusive, meaning the first address itself counts as one of the 2048 addresses.

Last Address = Starting Address + (Total Addresses - 1)

Last Address = CC00 + (2048 - 1)

Last Address = CC00 + 2047

4. Hexadecimal Addition:

To add CC00 and 2047 in hexadecimal format:

• Convert 2047 to hexadecimal: 2047 (decimal) = 07FF (hexadecimal).
• Add CC00 (starting address) and 07FF (hexadecimal representation of 2047).

CC00 + 07FF = D3FF

Therefore, the last address of the byte in this RAM is D3FF.

Correct Answer: Option 3 (D3FF)