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A machine is coupled to a two-stroke engine which produces a torque of (T) = [800 + 180 sin 3 θ] (N.m)

Where θ is the crank angle. The mean engine speed is 600 rpm. What will be the power of engine? [π = 3.14]

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  1. 20.51 kW
  2. 50.24 kW
  3. 60.17 kW
  4. 30.62 kW

Answer (Detailed Solution Below)

Option 2 : 50.24 kW
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Detailed Solution

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Concept:

Power developed by a rotating shaft is given by:

Where, is the mean torque and is the angular speed in rad/s.

Given:

Torque, 

Speed, N = 

Calculation:

Since the average of a sine function over a complete cycle is 0, the mean torque:

Angular velocity,

Power,

 

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