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A Hall-effect element is used for the measurement of magnetic field of 0.8 Wb/m2. The thickness of the element is 2.5 mm and is of bismuth material. If the current passed through the element is 4A, then the Hall emf developed will be: (Hall coefficient is 5 × 10-7)

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UGC NET Paper 2: Electronic Science Dec 2018 Official Paper
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  1. 1.4 × 10-4 V
  2. 6.4 × 10-4 V
  3. 2 × 10-7 V
  4. 3.2 × 10-4 V

Answer (Detailed Solution Below)

Option 2 : 6.4 × 10-4 V
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Detailed Solution

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Concept: 

The hall voltage VA is given by:

ρc: Charge density

RH: Hall coefficient

W is the side across which the magnetic field is applied.

Calculation:

W = Thickness = 2.5 mm, I = 4A, RH = 5 x 10-7, B = 0.8 Wb/m2  

VH =  6.4 × 10-4 V

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