A coin is tossed twice, then find the probability that head is obtained atleast once.

Question

Question

Answer 1

Formula used:

Probability = \(\frac{Number\ of \ favourable \ events}{Total \ events}\)

Calculation:

When a coin is tossed twice, then the possible outcomes,

n(S) = {HH, HT, TH, TT} = 4

If the head is obtained at least once, the possible outcomes,

n(P) = {HH, HT, TH} = 3

Hence, the required probability

P(E) = \(\frac{n(P)}{n(S)}\)

⇒ P(E) = \(\frac{3}{4}\)

Hence, option 3 is correct.