Question
Download Solution PDFA block of mass 20 kg is moving with velocity 10 m/s on a rough horizontal surface. Maximum amount of heat that can be generated from this block is _______.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCONCEPT:
- Energy conservation: The energy of an isolated system is conserved the energy may be transformed from one form to another form.
- Energy can neither be created nor destroyed.
- The kinetic energy of a mass is given by
\(KE = {1 \over 2}mv^2\)
where m is the mass, v is the speed and KE is the kinetic energy.
CALCULATION:
- Given that m = 20 kg; v = 10 m/s
- According to the law of conservation of energy, energy can neither be created nor be destroyed. It only transforms from one form to another form.
- So maximum heat will be generated when this block's whole kinetic energy is converted into heat energy. So
Maximum heat energy finally = total kinetic energy initially
Maximum heat energy finally = \( {1 \over 2}mv^2= {1 \over 2} \times 20 \times 10^2=1000 J\)
Maximum heat generated = 1000 J = 1 kJ
- So the correct answer is option 1.
Last updated on Jul 4, 2025
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