A beam of length L is pinned at both ends and is subjected to a concentrated bending couple of moment M at its centre. The maximum bending moment in the beam is

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BPSC AE Paper 5 (Civil) 14 Oct 2022 Official Paper
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  1. M
  2. M/2
  3. ML
  4. ML/2

Answer (Detailed Solution Below)

Option 2 : M/2
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Detailed Solution

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Explanation:

The beam under the given loading is

Taking moment about the point A, we get

M0 - RB × L = 0

RB = M0/L (↑)

Taking, Σ V = 0

RA + RB = 0 (As there is no vertical loading)

RA =  M0/L (↓ )

So, the FBD of the above beam can be drawn as

So, the SFD will be

From, the SFD we can say that the maximum shear force will be M0/L throughout the beam, including the midsection.

BMD

The maximum bending moment in the beam is

= M/2 or Mo/2

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