Question
Download Solution PDFA, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If 3P(B) = 4P(A) and 3P(C) = 2P(B), then what is P(A) equal to?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
A, B and C are mutually exclusive and exhaustive events:
⇒ P(A) + P(B) + P(C)= 1.....(i)
Also
⇒ 3P(B) = 4P(A)
⇒ P(A) = \(\frac{3}{4} P(B)\)
and 3P(C) = 2P(B)
⇒ P(C) = \(\frac{2}{3}P(B)\)
From (i)
⇒ \(\frac{3}{4}P(B) +P(B)+ \frac{2}{3}P(B) =1\)
⇒ \(\frac{9P(B)+12P(B)+8P(B)}{12} = 1 \)
⇒ \(\frac{29P(B)}{12} =1\)
⇒ P(A) = \(\frac{3}{4} \times \frac{12}{29} = \frac{9}{29}\)
∴ Option (c) is correct.
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