A 60 Hz, 4 pole turbo generator rated 100 MVA, 13.8 KV has an inertia constant of 10 MJ/MVA. Find the stored energy in the rotor at synchronous speed.  

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  1. 10 MJ 
  2. 100 J 
  3. 1000 J
  4. 1000 MJ 

Answer (Detailed Solution Below)

Option 3 : 1000 J
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Explanation:

Stored Energy in the Rotor of a Turbo Generator

Problem Statement: A 60 Hz, 4-pole turbo generator rated 100 MVA, 13.8 kV has an inertia constant of 10 MJ/MVA. The task is to calculate the stored energy in the rotor at synchronous speed.

Solution:

The key to solving this problem lies in understanding the relationship between the inertia constant (H), the apparent power (S), and the stored kinetic energy of the rotor (Wstored) at synchronous speed. The inertia constant is defined as the energy stored in the rotor per unit of the generator's apparent power (MVA rating) at synchronous speed.

Given Data:

  • Frequency (f): 60 Hz
  • Number of poles (P): 4
  • Apparent power (S): 100 MVA
  • Inertia constant (H): 10 MJ/MVA
  • Voltage rating: 13.8 kV (not needed for this calculation)

Formula:

The total stored energy in the rotor at synchronous speed can be calculated using the formula:

Wstored = H × S

Where:

  • Wstored is the total energy stored in the rotor (in MJ).
  • H is the inertia constant (in MJ/MVA).
  • S is the apparent power rating of the generator (in MVA).

Substituting the Given Values:

Wstored = 10 MJ/MVA × 100 MVA

Wstored = 1000 MJ

Final Answer: The stored energy in the rotor at synchronous speed is 1000 MJ.

Additional Information

To analyze why the other options are incorrect, let us revisit the problem:

Option 1: 10 MJ

This is incorrect. The inertia constant (H) is 10 MJ/MVA, meaning the stored energy per MVA is 10 MJ. Since the generator has a rating of 100 MVA, the total stored energy is 100 times this value, or 1000 MJ. Option 1 does not account for the multiplication by the apparent power of the generator.

Option 2: 100 J

This is incorrect. The unit of energy given in this option (Joules) is inconsistent with the unit of the inertia constant (MJ/MVA). Furthermore, 100 J is an extremely small value for the stored energy in the rotor of a generator rated at 100 MVA. This value is not realistic for the given scenario.

Option 3: 1000 J

This is incorrect. Similar to Option 2, the unit of energy in this option (Joules) is inconsistent with the given data. Additionally, 1000 J is a negligible amount of energy for a generator of this size and rating. The correct answer must be expressed in megajoules (MJ), not joules (J).

Option 4: 1000 MJ

This is the correct answer. As calculated above, the total stored energy in the rotor is 1000 MJ, derived from multiplying the inertia constant (10 MJ/MVA) by the apparent power (100 MVA).

Option 5: (Not provided in the problem)

There is no fifth option in the problem description, so this does not need further analysis.

Conclusion:

The correct option is Option 4: 1000 MJ. This value accurately represents the total stored energy in the rotor of the turbo generator at synchronous speed, based on the given inertia constant and apparent power rating.

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