Question
Download Solution PDFA 10 tonne refrigeration system consumes 10 kW of electrical energy. It's Coefficient of Performance will
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The coefficient of performance is the ratio of heat extracted in the refrigerator to the work done on the refrigerant.
COP (Coefficient of Performance) of the ideal refrigerator
\(COP = \frac{{{Q_1}}}{W_R} = \frac{{{T_1}}}{{{T_2} - {T_1}}}\)
where T2 = Temperature of the hot reservoir, T1 = Temperature of the cold reservoir, Q1 = Heat rejected from the cold reservoir, WR = Work required to pump the heat out.
Calculation:
Given:
A 10-tonne refrigeration system
1 tonne = 3.5 kW hence, 10 tonne = 35 kW
Q1 = 35 kW
Refrigeration system consumes 10 kW of electrical energy.
WR = 10 kW
\(COP =\frac{Q_1}{W_R} = \frac{{35}}{{10}} = 3.5\)
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